the digit at tens place of a two digit number is two times the digit at 1 present 27 is subtracted from the number its digits are reversed find the number​

Step-by-step explanation:

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It said

The Number at tens position is twice that at unit

therefore

If the unit number is x

The Tens Number will be= 2x

Now

Grab this concept

If we want to write a 2digit number 49

we can say 10x4 + 9 which is the same as 49.

So

The original number is 10x2x + x

Now

27 is subtracted from this number and the digits are reversed

When the digits are reversed; The Tens position will now be x and Unit will be 2x... This new 2digit number will be 10xX + 2x

So applying what we know

27 - (Original number) = Reversed

27 - (10x2x + x) = 10xX + 2x

27 = 10xX + 2x + (10x2x + x)

27 = 10x +2x + 20x + x

27 = 33x

x = 27/33

x=9/11

The original Number is 10x2x + x

= 10x2(9/11) + 9/11

=10x18/11 + 9/11

180/11 + 9/11

=189/11.

true

explanation: