In right triangle ΔABC, ∠C is a right angle, AC = 20 and m∠A = 41º. Find AB to the nearest tenth. I NEED HELP ASAP
PLEASE STEP BY STEP

AB = 26.5º

Step-by-step explanation:

cosA = adj/hyp

cosA = AC/AB

cos41 = 20/AB

Multiply both sides by AB

AB * cos41 = 20

Divide both sides by cos41

AB = 20/cos41

AB = 26.5º

Explanation:

ΔABC is right in the angle ∠C

in this case AB is the hypotenuse of the triangle ABC

according to the given data we will use the length of AC which is the adjacent side to the angle ∠A and the Cosine of the angle ∠A in the following formula:

the hypothenuse = adjacent side / cosine of the angle

AB = 20 / cos(41°)

AB = 26.5

14

step-by-step explanation:

14 x 3 = 42

ou would have 12 of each