A box contains eight cards numbered 2, 3, 4, 5, 6, 7, 8, 9. One card is selected at random and replaced. What is the probability that you can select a 2 and then a prime number?

1/2

Step-by-step explanation:prime numbers ={2,3,5,7}

likelihood of prime numbers =number of prime numbers /all numbers

                                                  =4/8 , 4 divides itself once and 4 divides 8 twice.

                                                  =1/2

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

hdjd

step-by-step explanation: