I need help ASAP For which function and interval can the extreme value theorem be applied?

f (x) = StartFraction x Over (x minus 6) squared EndFraction over the interval [3, 5]
f (x) = StartFraction negative 5 Over 2 (x minus 7) cubed EndFraction over the interval (6, 8)
f(x) = 4 tan(πx) over the interval [0, 1]
f(x) = 3ex + 1 over the interval (1, 3)

A) f(x)=x/(x-6)^2 over the interval [3, 5]

Step-by-step explanation:

got it right on edge :) good luck!

A

Step-by-step explanation:

I got it correct

whatare you sayig

step-by-step explanation:

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45