Pls help i need to know what x/-4 + 6 < 11 is?!?!!?!?!

Answer:

x ∈ ( - ∞ , 20 )

Step-by-step explanation:

Given :

x / 4 + 6 < 11

Adding - 11 both we get:

= > x / 4 + 6 - 11 < 11 - 11

= > x / 4 - 5 < 0

Multiply by 4 both we get:

= > x - 20 < 0

Adding 20 both side we get:

= > x - 20 + 20 < 20

= > x < 20

Solution set x ∈ ( - ∞ , 20 )

Hence we get required answer!

9514 1404 393

  x > -20

Step-by-step explanation:

This is a "2-step" inequality with a negative coefficient.

  x/-4 +6 < 11 . . . . . given

  x/-4 < 5 . . . . . . . . subtract 6 from both sides

  x > -20 . . . . . . . . .multiply both sides by -4

Because the multiplier is negative, the sense of the comparison must be reversed.

Check

  x = -24 should not be in the solution set: -24/-4 +6 < 11 ⇒ 12 < 11 . . . False

  x = -16 should be in the solution set: -16/-4 +6 < 11 ⇒ 10 < 11 . . . True

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44