Peter was in a line. There were twice as many students in front of him as behind him. Students (more than 3 but fewer than 9) left the line but Peter did not. Then twice as many students were behind Peter as in front. How many students left the line?

6 people left

Step-by-step explanation:

4 behind him 8 infront 6 left from infront leaving 4 behind 2 infront

Explanation:

x = the number of students in front of peter

y = the number of students behind peter

z = the number of students who left, for 3 < z < 9 ∴ z ∈ {4, 8}

system of equations:

x = 2y ⇒ y = x/2 (defining y with x)

2(x-z) = y (lets substitute y)

2(x-z) = x/2

2x-2z = x/2

2(2x-2z) = x

4x-4z = x

4x-x = 4z

3x = 4z

if z = 6 (i pluged the numbers from 4 to 8)

then

3x = 4×6

3x = 24

x = 24/3

x = 8

∴ y = 4

8 students were in front of peter and 4 were behind him

6 left

now 2 students are in front of peter and 4 are behind him

8 is twice 4

8-6 = 2

4 is twice 2

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: