Circle A has a radius of 12 in., m( arc BC )=π/6, m( arc CD ) = π/4. What is the area of the sector with the central angle ∠BAD?

Area of the sector = 94.25 in²

Step-by-step explanation:

From the picture attached,

Length of the radius of the circle = 12 in.

m(arc BC) =

m(arc CD) =

Therefore, m(arc BD) = m(arc BC) + m(arc CD)

m(arc BD) =

                 =

Since, area of a sector with central angle 'θ' is given by,

Area of the sector =

By substituting the measures in the given formula,

Area of sector BAD =

                                  =

                                  =

                                  = 94.25 in²

37

step-by-step explanation: