Judy is solving a quadratic equation using the quadratic formula. When she substitutes her valuesinto the formula, the discriminant is equal to 0. What does this tell her about the equation and graph? (1) There is no solution so the graph would be a parabola that does not intersect the x-axis
(2) There is one solution so the graph would be a line
(3) There is one solution so the graph would be a parabola that only intersects the x-axis once
(4) There are two solutions so the graph would be a parabola that intersects the x-axis in two locations

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

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chiken

step-by-step explanation:

do your own work and don"t cheat.

step-by-step explanation: