Pls help this is probably super easy but not for me A student is standing 20 feet away from the base of a tree. he looks to the top of the tree from a 50 degree angle of elevation. His eyes are 5 feet above the ground. using cos 50°≈0.64, what is the height of the tree to the nearest foot?

A. 29 feet
B. 24 feet
C. 31 feet
D. 36 feet

A.    29 feet

Step-by-step explanation:

Use cos to find the hypotenuse

cos  = adj/hp

0.64 = 20/hyp

hyp = 20/0.64

hyp = 31.25

Use Pythagorean Theorem to find the height of tree above eyes

a² + b² = c²

a² + 20² = 31.25²

a² = 31.25² - 20²

a² = 576.5625

a = 24  (to the nearest foot)

Finally add in the eye height

h = 24 + 5

h = 29 feet

A. 29 feet

Step-by-step explanation:

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the answer to this is:

factor 2x2+16x+24

2x2+16x+24

=2(x+2)(x+6)

answer:

2(x+2)(x+6)

hope this hmu if needed