James is painting a portrait. He is using a canvas that has a width of 18 inches and a height of 20 inches. Find the location of a focal point on the portrait using the golden ratio
Hint Assume the golden ratio is 1.6181

A. A focal point is located 11.124 inches to the left of the right edge of the canvas and 12.36 inches above the bottom
edge of the canvas

B. A focal point is located 17382 inches to the left of the right edge of the canvas and 19.382 inches above the bottom
edge of the canvas

C. A focal point is located 0.09 inches to the left of the right edge of the canvas and 0.081 inches above the bottom edge
of the canvas

D. A focal point is located 16.382 inches to the left of the right edge of the canvas and 18.382 inches above the bottom
edge of the canvas

step-by-step explanation:

cats

i think its a and d

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v