ABCD is a rhombus. The diagonals intersect at point E. If angle CDB= 6x and angle ACD= 2x+10, find x.

x =

Step-by-step explanation:

The diagonals of a rhombus are perpendicular to each other, thus the angle at point E is . So that ΔCED is a right triangle, and that;

<CDB = <CDE

<ACD = <ECD

<CDE + <ACD + <CED = (sum of angles in a triangle)

6x + (2x + 10) + =

8x + 100 =

8x = - 100

8x = 80

x =

  =

Thus, the value of x is .

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

goog may be able to you find that answer