For a 95% confidence interval what would the sample size need to be as it's most conservative to have a 2% margin of error

The size of the sample 'n' = 2401

Step-by-step explanation:

Step:1

Given that the margin of error = 2 % = 0.02

The margin of error is determined by

we know that the proportion

Step:2

The margin of error is determined by

              √n  = 49

Squaring on both sides, we get

                n = 49 × 49

                n = 2401

Final -

The size of the sample 'n' = 2401

the answer is a

step-by-step explanation: