1. One vertex of an equilateral triangle is A (0,0) and another is B (10,0). Let C be the third vertex, and let M be the midpoint of side BC. What is the slope of line AM? 2. Find the equation of the circle that has its center at the origin and is tangent to the line y=2x−2.
3. Find the coordinates of the point on the line y= -5x/12 + 5 nearest to the origin.

can you assist with the question and not reply with I don't understand the question like a previous response.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

step-by-step explanation:

what grade level is this? need to know so i can look in my old textbooks!

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2

there is no points to select.

step-by-step explanation: