When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval (CI) and margin of error (ME) for the true proportion of all college students who own a car.

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

%

then,

or,

Now,

The point estimate will be:

⇒  

⇒      

⇒      

or,

⇒  

⇒            

The margin of error will be:

⇒  

On substituting the above values, we get

⇒      

⇒      

⇒      

hence,

⇒  

⇒  

⇒  

a

step-by-step explanation: