What are the solutions to log (x² + 8) = 1 +logo(x)?

x = 9.125 and 0.875

Step-by-step explanation:

Given the expression

log (x² + 8) = 1 +log(x)?

This can also be written as;

log (x² + 8) = log 10 +logo(x)

log (x² + 8) =  log(10x)

(x² + 8) =  (10x)

x² -10x + 8 = 0

Factorize;

x = 10±√(-10)²-4(8)/2

x = 10±√100-32/2

x = 10±√68/2

x = 10±8.25/2

x = 10+8.25/2 and 10-8.25/2

x = 18.25/2 and 1.75/2

x = 9.125 and 0.875

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.