Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched. Remember the equation is in the form h(t) = -16x2 + v0x + h0 V0 is the initial velocity (48)

H0 is the initial height (0)

Graphon the coordinate plane. You may use Desmos graphing calculator to help.

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.

Jehhnd. rhehbf ehnd new e hw ended nehru shh snow rheh 6 cents!