Consider a circle with center (8,-4) that passes through the point (10,6). What is the equation of the described circle?
A) (x - 8)^2 + (y + 4)^2 = 104
B) (x - 8)^2 + (y + 4)^2 = 200
C) (x + 8)^2 + (y - 4)^2 = 104
D) (x + 8)^2 + (y - 4)^2 = 200

If the circle passes through the point (9,5), what is the equation of the new circle with the same center?
A) (x + 8)^2 + (y - 4)^2 = 178
B) (x + 8)^2 + (y - 4) ^2 = 82
C) (x - 8)^2 + (y + 4)^2 = 178
D) (x - 8)^2 + (y + 4)^2 = 82

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.

my guess is

step-by-step explanation:

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation: