Suppose you are choosing a 6 digit personal access code. This code is made up of 4 digits chosen from 1 to 9, followed by 2 letters chosen from A to Z. Any of these digits or letters can be repeated. Use the counting principle to find the total number of personal access codes that can be formed

4435236

Step-by-step explanation:

Total digits of code = 6

Code options for first 4 digits = any of 1 - 9 = 9 options

Code option for last 2 digits = A - Z = 26 options

Code number 1 = 9 possible values

Code number 2 = 9 possible values

Code number 3 = 9 possible values

Code number 4 = 9 possible values

Code number 5 = 26 possible values

Code number 6 = 26 possible values

Hence, total number of possible access codes :

9 * 9 * 9 * 9 * 26 * 26

9^4 * 26^2

= 4435236 possible ways

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

you divide them and then you get the answer i took this class this year

step-by-step explanation: