PLEASE PLEASE PLEASE HELP The opening of a train tunnel is shaped like a parabolic arch. The height of the opening is defined by the function h(x) = 6 - 0.4x ^ 2 , where x is the horizontal distance in meters from the centerline of the tunnel How wide is the tunnel's opening at ground level ? Round your answer to the nearest tenth of a meter .

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

angle efh= angle egh