Select the correct answer. Consider functions fand g. f(1) = 22 + 1 - 1 1-1 J(I) = 3 - 2 Using a table of values, what is the approximate solution to the equation f(T) = g(t)to the nearest quarter of a unit? OA 0.50 OB. I 7 – 1.75 Ос. I 0.75 DI -2.25​

add an image, and i will answer

step-by-step explanation:

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)