Suppose that the functions s and t are defined for all real numbers x as follows. s(x)=x-4
t(x) = 4x+6
Write the expressions for (s • t)(x) and (s-t)(x) and evaluate (s+t)(-1).
(s. t)(x) = 1
(s – t)(x) = 0
(s + t)(-1) = 0
?

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

f(x) is   are being squared

g(x) is   increasing by 2

h(x) is adding .25 each time

k(x) is taking the square root

f(x) and k(x) are exponential functions