If n is an integer, what is the sum of the next three consecutive even integers greater than 2n?​

6n + 12

Step-by-step explanation:

Given an integer n, the 3 consecutive even integers greater than 2n are 2n+2, 2n+4 and 2n+6

Taking their sum;

Sum = (2n+2)+(2n+4)+(2n+6)

Sum = 2n+2n+2n+2+4+6

Sum = 6n + 12

Hence the sum of the 3 consecutive even integers greater than 2n is 6n+12

1. 8

2. 9

3. 20

4. 3

5. 17

6. 2.2

7. 11.25

8. 1

9. 14

10. 2

step-by-step explanation:

thats the first half

25% is the answer