An automobile's velocity, starting from a complete stop, is v(t) =140t/5t - 6 where v is measured in feet per second. After what elapsed time would the automobile reach a

velocity of 44 Feet per second?

3.3 seconds

Step-by-step explanation:

v(t) =140t/5t - 6 where v is velocity

The time, t when, v = 44 ft/s

Put v = 44 ft/s in the equation :

44 = 140t / 5t - 6

44(5t - 6) = 140t

220t - 264 = 140t

-264 = 140t - 220t

-264 = - 80t

Divide both sides by 80

264 / 80 = 80t/80

3.3 = t

Hence, automobile will reach a velocity of 44 ft /s after 3.3 seconds

89

step-by-step explanation:

a - base

b - exponent

so,