The TSA decides to hold back for inspection 4% of all pieces of carry-on luggage. Assuming selections are independent, for the next 150 pieces of luggage, a) find the exact probability that 7, 8, or 9 will be selected. Interestingly enough, this is a case where two of our approximation methods may be appropriate. b) Using Poisson approximation, recalculate the probability from a), and compare. c) Using normal approximation, recalculate the probability from a), and compare

a) 0.3140

b) 0.3098

c) 0.3447

Step-by-step explanation:

Given data :

p = 4% = 0.04

Assuming selections are independent for next 150 pieces

n = 150

a) Probability that 7,8,9 will be selected

P( 7,8,9 ) = 0.3140

b) probability that 7,8,9 will be selected using Poison approximation

P( 7,8,9 ) = 0.3098

c) using normal approximation to determine the probability from ( a )

P ( 7,8,9 ) = 0.3447

Attached below is the detailed solution

answer: 0,6

step-by-step explanation:

this would make it the y intercept.