A model rocket is launched with an initial upward velocity of 188 ft/s. The rocket's height h (in feet) after t seconds is given by the following. h=188t-16t^2

Find all values of for which the rocket's height is 92 feet.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

0.51 and 11.24 seconds.

Step-by-step explanation:

The height h of a rocket with an initial upward velocity of 188 feet per second after t seconds is modeled by the function:

And we want to find all values of t for which the rocket's height is 92.

So, we can set h(t) = 92 and solve for t:

We can divide everything by four:

Rearrange the equation:

We can use the quadratic formula:

In this case, a = 4, b = -47, and c = 23. Substitute:

Evaluate:

Hence, our two solutions are:

So, the rocket reaches a height of 92 feet after 0.51 seconds and again after 11.24 seconds.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!