At the first pep rally of the season, the football team and the volleyball team were presented to the student body. During the pep rally, up to 11 players talked to the crowd. Football players talked about 17 seconds each and volleyball players talked
about 28 seconds each.

If the players only had a total of 242 seconds (4.03 minutes), which system of inequalities could be used to determine the
number of football players (6) and volleyball players (y) that could talk to the student body?

A. f+ < 11
17f+ 28 v 242

B. f+ v< 11
17v+28f< 242

C. f+ V< 11
17v+28f< 242

D. f+ V< 11
17f+ 28v 242

dont't really have enough info here but its likely

sss for the three sides being congruent ( its stands for side side side)

or

sas   for side angle side.   so a side is congruent and and angle and a side

answer: given the scale 3,5 mm to 1 foot: so you know this and you need convert this 150mm to get the right answer.

20/27

​​

step-by-step explanation:

1 simplify brackets

-\frac{8}{9}\times \frac{5}{6}−

​9

​

​8

​​ ×

​6

​

​5

​​

2 use this rule: \frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}

​b

​

​a

​​ ×

​d

​

​c

​​ =

​bd

​

​ac

​​

-\frac{8\times 5}{9\times 6}−

​9×6

​

​8×5

​​

3 simplify 8\times 58×5 to 4040

-\frac{40}{9\times 6}−

​9×6

​

​40

​​

4 simplify 9\times 69×6 to 5454

-\frac{40}{54}−

​54

​

​40

​​

5 simplify \frac{40}{54}

​54

​

​40

​​   to \frac{20}{27}

​27

​

​20

​​