Use the surface integral in Stokes' theorem to calculate the flux of the curl of the field F= x^2y i +y^3zj +3zk across the surface S: r(r, θ)= rcos θi + rsin θj +rk ; 0 <= r <= 2 ; 0<= θ <= 2π in the direction of the outward unit normal n.

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Step-by-step explanation:

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< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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