Find the volume and surface area of a rectangular box 3 ft by 1.2 ft by 6 ft The volume is 21.621.6 cubic feet. ​(Round to the nearest tenth as​ needed.) The surface area is nothing square feet. ​(Round to the nearest integer as​ needed.)

Volume = 21.6 ft³

Area = 58 ft²

Step-by-step explanation:

(1)

Applying,

V = lwh Equation 1

Where V = Volume of the rectangular box, l = length of the box, w = width of the box, h = heigth of the box.

From the question,

Given: l = 3 ft, w = 1.2 ft, h = 6 ft.

Substitute these values into equation 1

V = 3×1.2×6

V = 21.6 ft³

(2)

Applying

A = 2(lw+lh+wh) Equation 2

Where A = surface area of the box

Also substituting into equation 2

A = 2[(3×1.2)+(3×6)+(1.2×6)]

A = 2(3.6+18+7.2)

A  = 2(28.8)

A = 57.6 ft²

A = 58 ft²

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step-by-step explanation:

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.