I have an ABCD parallelogram and BC=AD=3√3,<BCD = 30⁰. How can I find the side CD?​

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)

answer: the right triangle the furthest one on the right

step-by-step explanation:

answer: 3 times more

step-by-step explanation: so the polar bear weighs 3 times more   than the black bear. so the grizzly weighs twice as much as the black bear. a good hint for word problems is to draw the problem out