![\frac{3}{5}](/tpl/images/1315/8538/62d38.png)
Step-by-step explanation:
GIVEN :-
Measure of side opposite to ā A (Perpendicular) = 6 unitsMeasure of side adjacent to ā A (Base) = 8 units
TO FIND :-
sin A
FACTS TO KNOW BEFORE SOLVING :-
![Hypotenuse = \sqrt{(Base)^2 + (Perpendicular)^2}](/tpl/images/1315/8538/cba8a.png)
![\sin A = \frac{Side \: opposite \: to \: A}{Hypotenuse}](/tpl/images/1315/8538/411c3.png)
PROCEDURE :-
Measure of perpendicular of triangle = 6 units
Measure base of triangle = 8 units
Measure of Hypotenuse = ![\sqrt{(6)^2 + (8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \: units](/tpl/images/1315/8538/d6afd.png)
Side opposite to ā A = Perpendicular of triangle = Ā 6 units
ā“ sin A = ![\frac{6}{10} = \frac{3}{5}](/tpl/images/1315/8538/b9780.png)