P(A) = 7/20 P(B) = 7/20 P(A or B) = 49/80, P(A and B)= ?​

P(A and B) = 7/80

Step-by-step explanation:

The given values of the probabilities of the different events are;

P(A) = 7/20

P(B) = 7/20

P(A or B) = 49/80

P(A and B) = Required

We have by probability theory for any event;

P(A or B) = P(A) + P(B) - P(A and B)

Therefore;

P(A and B) = P(A) + P(B) - P(A or B)

Plugging in the values gives;

P(A and B) = 7/20 + 7/20 - 49/80 = 7/80

∴ P(A and B) = 7/80

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