NEED HELP ASAP, WILL GIVE BRAINLIEST Find the x-intercept(s) and the coordinates of the vertex for the parabola y=x + 2x-15. If there is more than one x-intercept, separate them with commas,​

Step-by-step explanation:

y = x^2 + 2x - 15

To find the x-intercepts, factor out the right side:

y = x^2 + 2x - 15

= (x + 5)(x - 3)

This means that the x-intercepts are at (-5, 0) and (3, 0).

Method 1:

The x-coordinate of the vertex of a parabola is given by the following:

x = -b/2a, where a = 1 and b = 2

= -(2/(2×1))

= -1

Using this value of x gives y = -16

Therefore, the coordinates of the vertex is (-1, -16).

Method 2:

We can find the x-coordinate of the vertex by taking the derivative of y and equating it to zero:

y' = 2x + 2 = 0 ---> x = -1

Using this value of x into our equation, we get y = -16.

Therefore,

vertex: (-1, -16)

step-by-step explanation:

because it just is

4+3x hope you like mark as brainliest✔