From point P on the ground, the distance to an airplane is 3000 meters. When the altitude of the plane is 1000 meters, what is the angle of elevation of the airplane, to the nearest degree?

answer: this is not a question

step-by-step explanation: this is a answer

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.

2

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft