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Mathematics, 10.05.2021 06:10 babowmanjacob666

Solve the equation on the
interval [0, 2pi).

4(sin x)^2 – 2 = 0


Solve the equation on the
interval [0, 2pi).
4(sin x)^2 – 2 = 0

ansver
Answers: 2

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You know the right answer?
Solve the equation on the
interval [0, 2pi).

4(sin x)^2 – 2 = 0
...
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