For each set of three lengths determine if they can be the side lengths of a triangle

1) Yes

2) No

3) Yes

4) Yes

Step-by-step explanation:

Remember the rule: the sum of the two shortest sides must be bigger than the longest side. From there, the answers should be obvious. Just add up the smallest sides for each triplet of lengths and see if that is bigger than the largest side.

7 + 14 > 18, therefore this can be a triangle

3 + 8 < 17, therefore this can't be a triangle

3.2 + 9.0 > 11.5, therefore this can be a triangle

6 + 7 > 8, therefore this can be a triangle

c.

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: