Researchers at the National Cancer Institute released the results of a study that investigated the effect of weed-killing herbicides on house pets. The randomly sampled 400 dogs from homes where an herbicide was used on a regular basis, diagnosing lymphoma in 230 of them. Of 200 dogs randomly sampled from homes where no herbicides were used, only 25 were found to have lymphoma. For this problem, let p1 be the population proportion of dogs that get lymphoma from homes where herbicides are used and p2 be the population proportion of dogs that get lymphoma from homes where herbicides are not used. Researchers are interested in learning about the difference in the proportion of cancer diagnoses between the two groups. What is the 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

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step-by-step explanation:

step-by-step explanation: