Write an equation for a circle that has a center at (-6, 5) and passes through the
point (-11, 3).
Blank 1
Blank 2
(x - 6)2
(x-6)
(x + 6)2
(x + 6)
(x - 11)
(x - 11)
(x + 11)
(x + 11)
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Blank 4
(y - 5)
(y-5)
(y + 5)2
(y + 5)
29
14.5
337
129
(y - 3)²
(y - 3)
(y + 3)
(y + 3)

question:

could we have options?

hello! just here for points! though i wish i knew!

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb