A submarine has three navigational devices but can remain at sea if at least two are working. Suppose that the failure times are exponential with means 1 year, 1.5 years, and 3 years. Formulate a Markov chain with states 0 - all parts working, 1,2,3 - one part failed, and 4 two failures. Compute EoT4 to determine the average length of time the boat can remain at sea.

your answer is 23/2 - 13.5

step-by-step explanation:

7/2 evaluates to

multiply x and 4.5

multiply x and 1

the x just gets copied along.

the answer is x

x

4.5*x evaluates to 4.5x

multiply 3 and 4.5x

multiply 1 and x

the x just gets copied along.

x

4.5*x*3 evaluates to 13.5x

7/2-4.5*x*3 evaluates to

  + 8 =

the answer is

7/2-4.5*x*3+8 evaluates to

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

tube or goog would be a great resource to with that question

the anwser is d) 75°

step-by-step explanation: