A store is giving out cards labeled 1 through 10 when customers enter the store. If the card is an even​ number, you get a 10​% discount on your purchase that day. If the card is an odd number greater than​ 6, you get a 40​% discount.​ Otherwise, you get a 25​% discount. The table shows the results of 200 customers. What is the relative frequency for each​ discount? Use pencil and paper. If the manager of the store wants approximately half of the customers to receive the ​25% ​discount, does this seem like an appropriate​ method? Explain.

step-by-step explanation:

10.50 + taxes which added up to 11.50

the answers c

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)