Find the mean, median, and mode(s) of the data with and without the outlier. 45, 52, 17, 63, 57, 42, 54, 58

Mean = 48.5, Median = 53, Mode = nothing, Outlier = 17

Step-by-step explanation:

Mean: Add all the numbers (388) then divide by how many numbers (8) are there. (= 48.5)

Median: Is the middle number () so you have to order them from least to greatest (17, 42, 45, 52, 54, 57, 58, 63) and then just keep marking them off left, right, left, right... until you get to the middle. But since there are two numbers (52, 54) you have to add them (106) then you divide by 2 (53).

Mode: Is the number that shows up the most. In this case none of them do.

Outlier: The number that is farthest from the other numbers (17).

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

it would take 5 hours i think idk i'm not that good at math.can you me with my questions i need asap.