A rectangular page is to contain 30 quare inches of print. The margins at the top and bottom of the page are to be 2 inches wide. The margins on each side are to be 1 inch wide. Find the dimensions of the page such that the least amount of paper is used.

Step-by-step explanation:

Print

xy = 30

x = 30/y

f(y) = 2x + 2y = minimum

f(y) = 2(30/y) + 2y = minimum

f'(y) = 2 - 60/(y^2)

0 = 2 - 60/(y^2)

60/(y^2) = 2

y^2 = 30

y = √30

√30 * x = 30

x = √30

print: √30 x √30

2

Paper

you have to add 2 to the length and width because the paper margins are 1 on each side

√30 + 2 x √30 + 2

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)