Find five find pairs of whole numbers, such that when they are inserted into the equation below, the solution of the equation is 2/5.

easy math just plug in a and b

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

first the equation needs to be simplified. so the equation would now look like:   52-24+11

then you multiply.

and when you multiply, you will get the answer of 39.  

if your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

max = c - (b2 / 4a).

the first step is to determine whether your equation gives a maximum or minimum.

-x2 + 4x - 2.     thats an example hope it