Multiply to give you 10 and add to give you 7.

so what you mean

Steps:

a. xy = 10

b. x+y = 7

x+y = 7

y = 7 - x

xy = 10

x(7 - x) = 10 (substitution of y)

7x - x² = 10

-x² + 7x - 10 = 0

here we have a quadratic equation that we will solve by using the quadratic formula

a = -1 | b = 7 | -10

x = (-7±√((-7)²-4×(-1)×(-10)))/2×(-1)

x = (-7±√(49-40))/-2

x = (-7±√9)/-2

x = (-7±3)/-2

x = -4/-2 , -10/-2

x = 2 , 5

check:

2×5 = 10

2+5 = 7

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."