Given the system of linear equations: \(\left\{ x+6y=6y=13x−2 \right.\) Part A: Graph the system of linear equations. Part B: Use the graph created in Part A to determine the solution to the system. Part C: Algebraically verify the solution from a Part B

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation:

(x) - (y) = (1 + 4i)

the second option

step-by-step explanation: