In ΔBCD, \overline{BD} BD
is extended through point D to point E, \text{m}\angle BCD = (2x-1)^{\circ}m∠BCD=(2x−1)
∘
, \text{m}\angle CDE = (7x-19)^{\circ}m∠CDE=(7x−19)
∘
, and \text{m}\angle DBC = (x+10)^{\circ}m∠DBC=(x+10)
∘
. Find \text{m}\angle CDE. m∠CDE.

$27.5

step-by-step explanation:

$110.00 divided by 4

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %

did you get the answer?