HELP!! WILL MARK BRAINLIEST A bag contains 2 red marbles, 3 blue marbles, and 4 green marble. What is the
probability of choosing a red marble, replacing it, then drawing a green marble?

A bag contains 2 red marbles, 3 blue marbles, and 4 green marble. What is the
probability of choosing a red marble, and without replacing it, then drawing a green
marble?

2 and 3

Step-by-step explanation:

Because it is the same thing

1/9

Step-by-step explanation:

So we have a total of 9 balls.

The chance of getting a red marble is 2/9

But since we dont replace it, the number drops.

There is now a total of 8.

The probability for getting a green is 4/8 or 1/2.

2/9*1/2 is 1/9

4 & 3

step-by-step explanation:

factor of 108=2×2×3×3×3=2×2×3^3=the number is 4 because 2 only occurs 2 times and 2×2=4 and factor of 2187=3^3×3^3×3=the number is 3 because 3 onlyvoccur 1 time.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0