We have a better understanding of the production rates for our Chase-a-Lot toys. Those toys are manufactured in weekly cycles. The machine runs for six days
straight. Over those six days, the machine produces toys at a rate of f(x)=x/20(√3x^2+4
(in thousands of toys per day). After running for six days, the
machine is taken off-line for maintenance on the seventh day, and then the cycle
starts all over again the following week. If each Chase-a-Lot toy requires three
yards of yarn, and there are approximately 350 yards of yarn per skein, how many
skeins of yarn should we order from our supplier each week?

tip $2.90

total $17.40

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

copyright potato 2019.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

middle maybe?

step-by-step explanation: