Some red, white, and blue candies were placed in a bowl. Some contain nute, and some do not suppose one of the candies were chosen randomly from all
the candles in the bowl. According to the table below, if the candy le blue,
what is the probability that it does not contain any nute?
Red White Blue
Nuta 10 20 20
No nutel 10 10 30
A. 40%
B. 60%
C. 10%
D, 20%

Option B: 60%

Step-by-step explanation:

The number of blue candies with nuts = 20

The number of blue candies without nuts = 30

The total number of blue candies = 20 + 30 = 50

As the chosen candy is blue, the probability that is does not contain any nuts will be = (The number of blue candies without nuts)/(Total number of blue candies)

So, the probability = 30/50 = 0.6 *100% = 60%

i believe that the answer is

b. y-1=-2(x-4)

hope this !