A wire 5.3 m long is attached to the top of a flagpole that leans to the left in a strong wind. The wire is anchored to the ground 1.2 m to the right of the pole. The wire forms a 68∘ angle with the ground. In order to find the height of the flagpole, how would you draw the diagram?

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

17 1/3

step-by-step explanation:

sine

step-by-step explanation: