The point Q(0, -1) is translated 6 units up. What are the coordinates of the resulting point, Q′?

Q' (0,5)

Step-by-step explanation:

We know that original point Q is (0, -1), we are then told that it has been translated 6 units up. With being asked what is the new point coordinates, or Q'.

To solve, first we need to know what axis belongs to what.

X is left and right

Y is up and down.

Since we know that Q' is 6 units higher than Q, we need to increase the value in the y axis. (x,y)

-1 + 6

5

Therefore the coordinates to Q' is (0,5)

∠cbe and ∠deb are same-side interior angles.

i took the test

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.